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Fuel cell water is potable after a small amount of treatment. It is just hot after leaving the fuel cells and need to cool a bit in storage tank for drinking.
The three fuel cells of the Space Shuttle produce more than enough water for 7 astronauts, three much smaller fuel cells should have no problem supporting 2 astronauts.
back-up batteries are not needed, if we use an expendable "orbit keeping pack". If a fuel cell fails (which is unlikely) during the mission of the lander, we can still abort the landing on two fuel cells, instead of risking the life of the crew.
Important would be a good separation between the fuel cells (not repeating Apollo 13, in which a single failure "destroyed" all three fuel cells).
Dropping a fuel cell makes little sense, it means more weight for extra plumbing and special electrical components (power contactors) than the fuel cells weights. It would be better having an additional set of hydrogen/oxygen tanks on the landing part, that operates the fuel cells until ascent.
Lets plan for ten days and just assume we scale the power demands of the Shuttle down by crew size alone (which means luxurious amounts of electricity for ten days):
Oxygen: 669.5 pounds = 303.6 kg (includes oxygen for ECLSS)
Hydrogen: 78.85 pounds = 35.77 kg (includes hydrogen for fuel cell purge).
Every Space Shuttle fuel cells provides maximal 10 kW continuous DC power, by just scaling down, we would operate the spacecraft at maximal comfortable 8.5 kW continuous DC power (2.86 kW per fuel cell).
The LM needed just a tiny fraction of this.
http://ntrs.nasa.gov/archive/nasa/casi.ntrs.nasa.gov/20090016295_2009014422.pdf
Note the slide saying, that the LM was initially designed for using fuel cells as well, coupled with a peaking battery and charger. Using batteries made the LM 43.5 kg heavier than the design with fuel cells, but had lower costs and less technological risk.
4 kW electricity maximal, and all together 65 kWh for a 35 hour stay on the moon.
So, batteries would really not cut it if we want to stay there for 10 days... but for ten days, our Lander would be a tiny bit small.
The three fuel cells of the Space Shuttle produce more than enough water for 7 astronauts, three much smaller fuel cells should have no problem supporting 2 astronauts.
back-up batteries are not needed, if we use an expendable "orbit keeping pack". If a fuel cell fails (which is unlikely) during the mission of the lander, we can still abort the landing on two fuel cells, instead of risking the life of the crew.
Important would be a good separation between the fuel cells (not repeating Apollo 13, in which a single failure "destroyed" all three fuel cells).
Dropping a fuel cell makes little sense, it means more weight for extra plumbing and special electrical components (power contactors) than the fuel cells weights. It would be better having an additional set of hydrogen/oxygen tanks on the landing part, that operates the fuel cells until ascent.
Lets plan for ten days and just assume we scale the power demands of the Shuttle down by crew size alone (which means luxurious amounts of electricity for ten days):
Oxygen: 669.5 pounds = 303.6 kg (includes oxygen for ECLSS)
Hydrogen: 78.85 pounds = 35.77 kg (includes hydrogen for fuel cell purge).
Every Space Shuttle fuel cells provides maximal 10 kW continuous DC power, by just scaling down, we would operate the spacecraft at maximal comfortable 8.5 kW continuous DC power (2.86 kW per fuel cell).
The LM needed just a tiny fraction of this.
http://ntrs.nasa.gov/archive/nasa/casi.ntrs.nasa.gov/20090016295_2009014422.pdf
Note the slide saying, that the LM was initially designed for using fuel cells as well, coupled with a peaking battery and charger. Using batteries made the LM 43.5 kg heavier than the design with fuel cells, but had lower costs and less technological risk.
4 kW electricity maximal, and all together 65 kWh for a 35 hour stay on the moon.
So, batteries would really not cut it if we want to stay there for 10 days... but for ten days, our Lander would be a tiny bit small.
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